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Candidly speaking, since I started working on indices I haven't seen nor come accros a problem that could produce different bases as your own. As you made 9^(n+2) *3^(n+2) out of 27^(n+2)
All that is correct.
Because it was easier to cancel.
Now I have learnt that! Thanks much Bobbym!
All of that is correct but I have to interpret every bit of it.
It is properly written 27^(n+3) this means
Notice they are both very different.
27^n+2=27^n * 27^2
You should learn to latex or to use parentheses better.
In fact I have not seen an indicial problem being split to get different numbers as the base. like what is in #269.
I am sorry, I can not follow that. Please bracket it off.
I suppose the base must always be the same in each case. So I percieved it to be,
You can say a = (n+2), same principle.
It's 27^n+2, and not 27^a.
27^a = 9^a * 3^a
Please, I double check it I have edited.