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Topic review (newest first)

bob bundy
2013-08-08 18:21:39

hi Agnishom,

Let's start again, shall we.  Draw a right angled triangle with angle A, hypotenuse c, opposite a.  Draw another with hypotenuse c and opposite B.  See diagram below.

From the first sinA = a/c

from the second sinB = b/c

But sinA = sinB , therefore a/c = b/c , therefore a = b

Bob

bobbym
2013-08-08 01:56:01

I thought that you would have found post #2 particularly relevant.

Agnishom
2013-08-08 01:36:04

In that case are we not assuming that A + B = 90degree ?

zetafunc wrote:

Are you required to give a geometric proof?

Well, yeah. But I would love to see any other proofs you have

bob bundy
2013-08-07 09:02:47

Agnishom wrote:

What if they do not have?

Start with two right angled triangles, both with hypotenuse c.  Let one have angle A and the other B.

Use the equal sines property to show that a = b.  Then they are congruent.

Bob

zetafunc.
2013-08-07 03:25:35

Are you required to give a geometric proof?

Agnishom
2013-08-07 02:56:16

What if they do not have?

bob bundy
2013-08-07 02:43:11

They both have a side 'c'.

Bob

Agnishom
2013-08-07 01:02:06

{7/3} wrote:

Sin A=a/c and sin B=b/c then a=b ,so in two right triangles with angle A and B ,oposite side is a=b,hypottenuse is c,other side must be equal.thus two triangles are congruent,A=B

But the two right triangles are not congruent! You certainly cannot say that two right triangles containing equal angles are congruent.

Agnishom
2013-06-30 21:54:07

Thanks smile

{7/3}
2013-06-30 14:46:44

Sin A=a/c and sin B=b/c then a=b ,so in two right triangles with angle A and B ,oposite side is a=b,hypottenuse is c,other side must be equal.thus two triangles are congruent,A=B

bobbym
2013-06-30 14:21:23

Draw right triangles ABC and PQR.

Prove that B = Q





We know that Sin B = Sin Q so:



We can manipulate the above to

b / q = c / r = k

b = kq and c = kr







Pull the k^2 out to simplify.



So



ΔABC is similar to ΔPQR

B = Q

Agnishom
2013-06-30 13:18:06

Provided that A and B are acute angles and sin A = sin B, prove that A = B

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