Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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anonimnystefy
2013-06-24 22:10:34

You're welcome.

{7/3}
2013-06-24 22:10:01

Oh,yeah,thanks.

anonimnystefy
2013-06-24 21:47:26

Everything is correct except it should be -13 in the line equation. Good job!

{7/3}
2013-06-24 15:27:23

Hi,if my calculations are correct then the inversion point is (129/65,47/65)
EDIT:the problem isn't as hard as i thaught,i am getting the line 4x+7y+13=0,is it correct?

{7/3}
2013-06-24 11:10:45

Sorry,I won't be able to work on it for the next 9 hours,But i'll let you know what i get.

anonimnystefy
2013-06-24 09:35:28

How far did you make it with the problem?

{7/3}
2013-06-23 10:50:00

anonimnystefy
2013-06-23 07:52:58

Have you tried first finding the inverse of the point with respect to the circle?

{7/3}
2013-06-14 01:35:41

Given a circle (x-1)^2+(y+1)^2=16 and a point (5,6),what will be the reciprocation line of this point?