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Topic review (newest first)
- MathsIsFun
- 2005-11-15 16:17:50
Gee, good work there Flowers.
- Flowers4Carlos
- 2005-11-15 15:59:24
ahhh... a heart! yes i recognize those!! they are the ones that are always fluttering about chris evans. 
- angelpumpingas
- 2005-11-15 15:41:16
Omg... Thank you so much for your help. ^_^ It is greatly appreciated....
And <3 is just a symbol for a heart... I use it more than I should, really... But oh well. 
Thanks again!!
- Flowers4Carlos
- 2005-11-15 15:07:45
hi yaz angel!!
what does "<3" in your signature mean??? i see that expression being used a lot lately.
(1+sinθ)^(1/2) (1+sinθ)
------------------ = ----------- the left side is easier to work with
(1-sinθ)^(1/2) |cosθ|
(1+sinθ)^(1/2)
------------------ multiply everything by the "conjugate" of the denominator
(1-sinθ)^(1/2)
(1+sinθ)^(1/2)*(1+sinθ)^(1/2) (1+sinθ)^(2/2) 1+sinθ
------------------------------------ = ------------------------------ = ------------------
(1-sinθ)^(1/2)*(1+sinθ)^(1/2) [(1-sinθ)(1+sinθ)]^(1/2) (1-sin²θ)^(1/2)
1+sinθ
------------------ remember the identity cos²θ = 1-sin²θ
(1-sin²θ)^(1/2)
1+sinθ 1+sinθ
------------------ = ---------------- since √a ≥ 0, then √cos²θ > 0 ⇒ |cosθ|
(cos²θ)^(1/2) (cosθ)^(2/2)
1+sinθ 1+sinθ
--------- = ---------
√cos²θ |cosθ|
- angelpumpingas
- 2005-11-15 05:36:15
I'm really confused on problems with square roots... Can someone please explain to me how to do this problem? It would be greatly appreciated. ^_^ I'm sure it's something simple, but I'm so confused. 
√1+sinθ/1-sinθ = 1+sinθ/|cosθ|