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barandaman
2013-05-23 23:21:07

GOT IT! tghank you so much now i know what you mean, ahhhh thank you

barandaman
2013-05-23 23:14:51

#### bob bundy wrote:

hi barandaman

That last line is not quite correct.

Your pi terms have lost their denominator.

Put that in and you can cancel it throughout.  The expression is then much simpler.

Bob

I really am having trouble with the latex...

The pi terms are different, one is pi^e one is pi^*

bob bundy
2013-05-23 22:44:22

hi barandaman

That last line is not quite correct.

Your pi terms have lost their denominator.

Put that in and you can cancel it throughout.  The expression is then much simpler.

Bob

bobbym
2013-05-23 21:16:23

Hi bob bundy;

That is okay.

Use

barandaman
2013-05-23 21:15:34

tinypic.com/r/rgxlwy/5

It is the problem we looked at yesterday, to solve it we set PI=PI^e, so all that changes is the LHS term is PI^e.

Then I expand the RHS as seen, and get the result as shown initially in the first image. I have no idea how to convert that into the solution, which is:

Pi^e = Pi^* + (b/a)(y^* - ybar)

I hope this is clearer!

bob bundy
2013-05-23 21:10:36

hi bobbym,

Didn't see your post as I was taking a long time over mine.

Bob

bob bundy
2013-05-23 21:09:09

hi barandaman

here's the LHS using Latex.

I think you need to do two things.

(i)  tell us what the question asks

(ii) show how you got this far.

You start with square brackets math and end with square brackets /math

The code for the above is:

#### Code:

 $a \pi^e = a \pi^{\Psi} + \frac{b(y^{ \Psi} - {ybar})}{a+b^2}$

There is a code for the line over the y but I forget at the moment.  But ybar is clear I think.

Bob

bobbym
2013-05-23 21:03:54

Hi;

See if you can write the problem out larger too.

barandaman
2013-05-23 21:02:00

I will write it out neatly and take a photo because I have not learnt latex 5 minutes!

bobbym
2013-05-23 20:57:16

Hi barandaman;

What have you done so far?

barandaman
2013-05-23 20:29:43

tinypic.com/r/2u6gyef/5

Hi,