You are not logged in.
Post a reply
Topic review (newest first)
An interesting thing about this question:-
Thanks much! An answer I can understand. Also gratified to see that my approximation of 14.5' was not THAT far off (I did say it would be "a little higher" than the actual value).
Bob, here is something you might have fun finding out for yourself.
If the compression is one inch then the revised figures are
An arc of a circle is into what shape a rod gets bent if the bending moment (and cross section) are the SAME all along its length - which they can never be if the forces are only at the ends!.
hi bobbym and BeamReacher,
From these last two
I used trial and improvement to find a = 0.03370775.... radians.
This gives the radius as
From the top two equations
Using the value of R and the quadratic formula
d = 44.498509.....
(My earlier answer of 63 was because I had used 2641 rather than 2640.5 for the arc length.)
If the bar were, by some immense stroke of luck, to remain straight the axial pressure to reduce its length by one inch would be a small fraction of a pound per square inch.
This question seems to be about bending of a bar.
I guess my solution is not necessary, okay.
Mr. Moderator, if it please you, I would be very grateful if you could show me how to solve this problem.
This is available from Amazon. The problem is shown in the 'Look Inside' advert. The solution is not.