I just have to convince Agnishom and he can be a toughie.

I thought you were going to say he could be a tough cookie.

anonimnystefy

2013-04-15 00:49:25

Hi bobbym

What is the m's constant?

bobbym

2013-04-15 00:48:03

That's right! The other methods produce that answer too. If you program it you will get the same answer. They just are not necessary.

Agnishom

2013-04-15 00:45:08

Isn't it just 6/14 =3/7 ?

bobbym

2013-04-15 00:40:42

Hi;

That's what the calculation is up there. But it is overkill.

Agnishom

2013-04-15 00:40:33

Atlast, I am starting to understand

Nehushtan

2013-04-15 00:38:53

Let’s rephrase the original cookies question in a different way. Suppose the 14 cookies are lined up in a row. What is the probability that the 7th cookie from the left is a chocolate-chip one?

bobbym

2013-04-15 00:35:04

Yep, and there could be no fives or 4 fives before. Point is, we can say nothing about the 14 cards above.

Agnishom

2013-04-15 00:33:10

There are many different ways in which it can turn out to be a five.

anonimnystefy

2013-04-15 00:29:18

What information do you have about it? You do not look at the first 14 cards.

Agnishom

2013-04-15 00:28:13

bobbym wrote:

The fifteenth card has the same amound of information

Nope. When you have gone down to the fifteenth card you already have the information of the fourteen cards above