Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

Post a reply

Go back

Write your message and submit
:) :| :( :D :o ;) :/ :P :lol: :mad: :rolleyes: :cool: | :dizzy :eek :kiss :roflol :rolleyes :shame :down :up :touched :sleep :wave :swear :tongue :what :faint :dunno
Options

Go back

Topic review (newest first)

anonimnystefy
2013-04-01 14:44:27

Everything else seems okay to me.

You are welcome.

White_Owl
2013-04-01 14:39:54

Yes, of course. Thank you.

anonimnystefy
2013-04-01 10:32:10

Third line - in the denominator you have k1*k2*...*kn and you say below it "n times". It should be 1*2*...*kn and below it should be "kn times".

White_Owl
2013-04-01 10:28:04

anonimnystefy, thank you. I see the mistake now

So my new answer is:


Therefore, series converges for k>=2

anonimnystefy
2013-03-31 13:17:31

Well, the rest of his current work is okay. But that error is messing up the whole thing.

bobbym
2013-03-31 13:14:01

Hi;

That is what I mean, something is bad where I indicated. There could be further mistakes but that is where the first one occurs.

anonimnystefy
2013-03-31 13:09:23

White_Owl wrote:

I do not think there are mistakes:


Or are you talking about different equations?

The second line is not correc(k(n+1))!=1*2*3*...*(k(n+1)-1)*(k(n+1))

bobbym
2013-03-31 13:02:41

Your first line is good.



Shouldn't manipulations maintain equality with the original assertion?



That does not?

White_Owl
2013-03-31 12:54:10

I do not think there are mistakes:


Or are you talking about different equations?

bobbym
2013-03-31 12:10:38

Hi;



Something is wrong right there.

White_Owl
2013-03-31 11:31:44

The problem is:
For which positive integers k is the following series convergent?



My Answer:
For series to be convergent the next inequality should be true (by the Ratio Test):

Since we know that both k and n are positive we can omit absolute bars.

And now I simplify:


But since k is a constant this limit will never be less than 1. Therefore the series divergent for all possible k.

Did I make a mistake somewhere? Textbook is looking for a convergent series...

Board footer

Powered by FluxBB