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  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

Agnishom
2013-03-27 15:33:39

smile

I have problems with my multiplication tables too. Is it very important?

bob bundy
2013-03-27 08:00:07

FOR i = 1 TO 20
        j = 1
        REPEAT
          ans = j*5
          PRINT j;" x 5 = ";ans
          j = j + 1
        UNTIL j = 11
      NEXT i


Bob smile

bob bundy
2013-03-27 07:54:32

Yes, sorry about that.  My excuse is that I was being harassed by the slow re-load time on pages.  It was driving me mad.  Originally I just posted the method.  Then I had the idea to work out the answer but hide it.  But I was completely off track because I had been thinking that 'y' divided the line in the ratio a:b ie 2:3 so I posted a + b = 5.

Then I read the question properly (why don't I do this first???) and revised my answer.  In my annoyance I thought 6 and 3/5 ... 6 5s are 35 add 3 makes 38.  So a/b = 38/5.  Big whoops.  I realised that must be wrong because that wasn't what my diagram was telling me, but it took ages to get the edit screen to work so I could do 6 5s are 30 add 3.    Pathetic excuse but there it is.  I've admitted to the forum that I cannot do my five times table.  I'll write it out 20 times.

Bob  smile

ps.  Load speed back to normal now.

Agnishom
2013-03-27 00:57:21

The site is okay for me

Yes, I got the idea Thanks a million smile


But I would be happier if you clarified it to be 33/5

bob bundy
2013-03-27 00:46:50

hi Agnishom,

I have edited my hidden answer.  Hopefully, you'll like the correction better.

The distance (3,5) to (1,y) and the distance (-1,5) to 1,y) are the same by the properties of reflection.

So minimise by drawing a straight line from (-1,5) to (4,9)

I am finding the site very slow at the moment ... not sure if this is general or not.  It took 10 mins to make my last post, edit it and then correct the edit.

Hope what I have said is clear.

Bob

Agnishom
2013-03-27 00:36:24

This sounds very interesting.
But:
1. That is not the answer
2. How do I know that that is the shortest distance?

bob bundy
2013-03-27 00:27:48

OR

Reflect (3,5) in the line x=1 to give (-1,5)

Join this point to (4,9) to give the minimum distance.

EDIT: and the ratio is easily found by counting coordinate squares.



Bob

bobbym
2013-03-27 00:20:05

The standalone or the one bundled with geogebra.

Agnishom
2013-03-27 00:15:19

MAXiMA,
I don't know much about it

bobbym
2013-03-27 00:11:02

What CAS are you using?

Agnishom
2013-03-27 00:02:40

Okay

The CAS didn't help me much. I haven't got a clue about equating that to 0 (by hand)

bobbym
2013-03-26 23:42:08

jimmyR is his username.

Agnishom
2013-03-26 23:29:33

His username?

bobbym
2013-03-26 23:20:37

Yes, he is a member but he does not like forums.

If you can do it using a CAS that is okay too.

Agnishom
2013-03-26 23:17:54

I haven't got an idea to find the derivative except using a CAS.
Actually, I am not fully acquinted with Calculus.

Is your brother on this forum?

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