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Two triangles with sides in the same ratio are similar. So the angles are the same. Therefore you can just call t = 1 without losing any of the problem's conditions.
Yeah Thanks! I had difficulty understanding the cancellation
Okay thanks I managed to understand this
I have the following doubts:
So I put
and re-arranged to get
Different values of k will make different sized circles but all the resulting triangles will be similar => same three angles.
So it is ok to take a = √6, b = 2√2, c = 3√3
Use the cosine rule to get cosA and hence sinA.
I made it
If in a triangle,
What is the value of sin angle A?
Is it 8/27?