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Topic review (newest first)
Oh! So inequality inside parenthesis in the probability arithmetic means sum of probabilities of all events which satisfy the inequality?
I think this would be more clear. Don't you think?
Hopefully it is obvious that
exactly when or or ,
Similarly, you have observed that
exactly when or ,
What anonimnystefy is referring to in post #6 is that
where if is true and 0 if it is false.
This is also equal to
I hope this helps.
Well? Does anyone have an answer?
I am sorry, I do not understand your answer.
They are both 1. But if you multiply 1 by the probability that X is in fact 7 (or 8), and then sum over all values of X, you will get the probability.
Ok, then lets take the k=2.
In that case we have two X which satisfy the inequality in parenthesis: 7 and 8.
Now what is the values of
Can you tell me the values for a and b?
What is the value of Pr(TRUE)???
You need to find the probability that |X-3.2|>=18.3 . You can do that by summind the probabilities of all values of X for which that is hreater than 18.3 (which is in this case 0). And you probably know that 0<=0.01 .
Yes, I read the definition, but it is not enough, I need a practical example.
Which X should I put here to see the truth of this inequality?
That inequality means that the probability of the difference between X and mu being greater or equal to k*sigma is less than or equal to 1/k^2.
I do not understand it.
For example, if we have a pmf table:
Now, how to calculate it for lets say k=10? or for k=100?
What goes for X in the inequality and what is the result of Pr() function?