Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

Write your message and submit
|
Options

Topic review (newest first)

bobbym
2013-04-03 07:00:48

The answer to d) i) is in the other thread.

anonimnystefy
2013-04-03 07:00:23

It is working.

bobbym
2013-04-03 06:55:58

WorkingPrecision did not work?

anonimnystefy
2013-04-03 06:51:05

Ah, there it is. I found the AccuracyGoal and PrecisionGoal, but they didn't help.

Thanks!

bobbym
2013-04-03 06:43:06

Easy, use WorkingPrecision-> some number.

anonimnystefy
2013-04-03 06:41:27

Hi bobbym

How do I get more accuracy out of NIntegrate?

bobbym
2013-03-05 07:08:59

Here is more:

http://maxima.sourceforge.net/documentation.html

I got
romberg(1/(cos(x)+x^2), x, 0, 100);
1.828017700397752

which is accurate. By setting rombergit to 200 and rombergtol to 1E-10.

Now you need to get a bfloat in there somehow.

anonimnystefy
2013-03-05 07:03:18

I get 0.66666657420034.

Thanks for the links. I will try 'em out.

bobbym
2013-03-05 06:35:18

Set it  25. and rombergtol: 1.e-6, what happens?

You should know about these:

http://eagle.cs.kent.edu/MAXIMA/maxima_21.html

http://www.csulb.edu/~woollett/

get them if you do not.

anonimnystefy
2013-03-05 06:33:06

It is 11.

bobbym
2013-03-05 06:28:03

There should be a global variable called rombergit. What is its value?

anonimnystefy
2013-03-05 06:22:55

It is working and giving out: 0.66653268137515

bobbym
2013-03-05 06:21:27

Try adjusting rombergtol: 1.e-3

anonimnystefy
2013-03-05 06:19:48

It says "Romberg failed to converge".

bobbym
2013-03-05 06:14:20

Hmmm? Change that exp(-x) to sqrt(x) and change f(0,50 ) to f(0,1)