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- bob bundy
- 2013-01-31 03:01:28
hi 3rdMath
Welcome to the forum.
If you had an algebraic form for the general term, then you could do the job in one go with
As you have just 4 terms and no general term you will have to show that
The value for this constant has already been given in earlier posts.
Bob
- mttal24
- 2013-01-31 02:51:26
Well, to identify and prove a geometric progression the following can be used:
If
t2/t1=t3/t2=t4/t3=.....=tn/t(n-1)=r (and 'r' also represents common ratio)
then the sequence is a GP.
Here,
1/2^4 divided by1/2 is equal to 1/2^7 divided by 1/2^4.
Thus, you can show that it is a gp
- bobbym
- 2013-01-31 01:25:14
Hi n872yt3r;
7^2 = 49 and 10^2 = 100
- anonimnystefy
- 2013-01-31 01:20:27
n872yt3r wrote:
(2^4=16) (2^7=49) (2^10=100) 1/16+1/49=0.0829081632653061224489795183673...+1/100=0.09290816326530612244897959183673...+1/2=0.59290816326530612244897959183673...
That is not correct. 2^7 is not 49 and 2^10 is not 100...
- n872yt3r
- 2013-01-30 22:45:13
(2^4=16) (2^7=49) (2^10=100) 1/16+1/49=0.0829081632653061224489795183673...+1/100=0.09290816326530612244897959183673...+1/2=0.59290816326530612244897959183673...
- bobbym
- 2013-01-30 14:29:33
Hi;
That is a geometric series because each term has a common ratio which is
- 3rdMath
- 2013-01-30 13:55:32
Given the series 1/2 + 1/(2^4)+1/(2^7)+1/(2^10)
(i) show that this is geometric sequence..........can some1 help with this please