Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

Post a reply

Go back

Write your message and submit
:) :| :( :D :o ;) :/ :P :lol: :mad: :rolleyes: :cool: | :dizzy :eek :kiss :roflol :rolleyes :shame :down :up :touched :sleep :wave :swear :tongue :what :faint :dunno
Options

Go back

Topic review (newest first)

bob bundy
2013-01-31 03:01:28

hi 3rdMath

Welcome to the forum.

If you had an algebraic form for the general term, then you could do the job in one go with



As you have just 4 terms and no general term you will have to show that



The value for this constant has already been given in earlier posts.

Bob

mttal24
2013-01-31 02:51:26

Well, to identify and prove a geometric progression the following can be used:
If
t2/t1=t3/t2=t4/t3=.....=tn/t(n-1)=r  (and 'r' also represents common ratio)
then the sequence is a GP.
Here,
1/2^4 divided by1/2 is equal to 1/2^7 divided by 1/2^4.
Thus, you can show that it is a gp

bobbym
2013-01-31 01:25:14

Hi n872yt3r;

7^2 = 49 and 10^2 = 100

anonimnystefy
2013-01-31 01:20:27

n872yt3r wrote:

(2^4=16) (2^7=49) (2^10=100) 1/16+1/49=0.0829081632653061224489795183673...+1/100=0.09290816326530612244897959183673...+1/2=0.59290816326530612244897959183673...

That is not correct. 2^7 is not 49 and 2^10 is not 100...

n872yt3r
2013-01-30 22:45:13

(2^4=16) (2^7=49) (2^10=100) 1/16+1/49=0.0829081632653061224489795183673...+1/100=0.09290816326530612244897959183673...+1/2=0.59290816326530612244897959183673...

bobbym
2013-01-30 14:29:33

Hi;

That is a geometric series because each term has a common ratio which is

3rdMath
2013-01-30 13:55:32

Given the series 1/2 + 1/(2^4)+1/(2^7)+1/(2^10)
(i) show that this is geometric sequence..........can some1 help with this please

Board footer

Powered by FluxBB