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- mathsyperson
- 2005-11-07 02:55:31
In each case, if Ali had one more apple then he could share them all out equally. So, your answer is one less than the lowest common multiple of 4, 5 and 9. 4, 5 and 9 share no common factors, so their lowest common multiple is simply their product. 4x5x9 = 180, so the minimum number of apples Ali can have is 179.
Check: 179/4 = 44 r 3
179/5 = 35 r 4
179/9 = 19 r 8
- Gara
- 2005-11-07 01:44:07
Ali has x apples. Whether he divides the apples among 4 boys, 5 boys or 9 boys, the remainder is 3,4 and 8 respectively.
what is the smallest possible value of x?