Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

Login

Username

Password

Not registered yet?

Post a reply

Go back

Write your message and submit
:) :| :( :D :o ;) :/ :P :lol: :mad: :rolleyes: :cool: | :dizzy :eek :kiss :roflol :rolleyes :shame :down :up :touched :sleep :wave :swear :tongue :what :faint :dunno
Options

Go back

Topic review (newest first)

mathsyperson
2005-11-07 02:55:31

In each case, if Ali had one more apple then he could share them all out equally. So, your answer is one less than the lowest common multiple of 4, 5 and 9. 4, 5 and 9 share no common factors, so their lowest common multiple is simply their product. 4x5x9 = 180, so the minimum number of apples Ali can have is 179.

Check: 179/4 = 44 r 3
179/5 = 35 r 4
179/9 = 19 r 8

Gara
2005-11-07 01:44:07

Ali has x apples. Whether he divides the apples among 4 boys, 5 boys or 9 boys, the remainder is 3,4 and 8 respectively.

what is the smallest possible value of x?

Board footer

Powered by FluxBB