Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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That is true, but replying to "him" doesn't have a point either.
You may be right, but, as 'he' isn't advertising anything, I don't see the point.
Just a feeling.
Well, at least I have that going for me.
Wish I could get off but they won't take me. There is one major difference between me and that fellow, if you hit me on the head three times hard with a hammer you can change my mind.
WHAT! You must be joking! At least you are on this planet! And in honour (honor?) of the respect I have for you I hereby grant you lifetime permission to use Bob's constant whenever you wish, free of charge and without the requirement to acknowledge whose constant it is.
Not in my world, please. That k is important to me. I'm thinking of naming it "Bob's constant". So you'll have to pay royalties just to use it!
Nope, k is a constant, so I am thinking k = k^2.
Not that I know of.
hi bobbym and Stefy
Well it's not exactly a tough integral is it? So you could also say "Why not just do it yourself?" And I have, of course!
You mean (kh)^2, bobbym?