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Wow! That is amazing! Thank you!
Consider the numerator (ignoring the minus sign outside the fraction). Notice that the terms in and vanish so the highest power of is . Its coefficient is . Now look at the denominator. The highest power of is also and its coefficient is . Hence the limit as is
using the following rule:
and and then
Why do you think this is a job for Stoltz then?
It wasn't hard.
You got that far! How the heck did you get there?
I already got that much. That limit there is the problem...
I am trying to put it into the required form but the algebra is hideous.
The above limit equals 1 / 2 . But the limit is very difficult to handle.
That is right.
We are not allowed to split that limit?
Do you see the n/(p+1) part? It makes it not possible to use Stolz like that.
We need to use the binomial theorem here now.
No. I already looked at that page. It just gets the limit to the indeterminate from 0*infinity...
I know that it should be equal to 1/2 and the the Stolz theorem is supposed to be used, but I cannot get the final result...