You are not logged in.
Post a reply
Topic review (newest first)
- scientia
- 2013-01-07 20:48:04
You're welcome. 
- anonimnystefy
- 2013-01-07 12:17:22
Wow! That is amazing! Thank you! 
- scientia
- 2013-01-07 11:51:08
bobbym wrote:
The above limit equals 1 / 2 . But the limit is very difficult to handle.
Consider the numerator (ignoring the minus sign outside the fraction). Notice that the terms in and vanish so the highest power of is . Its coefficient is . Now look at the denominator. The highest power of is also and its coefficient is . Hence the limit as is
using the following rule:
If
and and then
- bobbym
- 2013-01-07 11:42:20
Why do you think this is a job for Stoltz then?
- anonimnystefy
- 2013-01-07 11:12:44
It wasn't hard.
I don't think ot would get much prettier...
- bobbym
- 2013-01-07 11:04:05
You got that far! How the heck did you get there?
Maybe we can use Stolz again?
- anonimnystefy
- 2013-01-07 10:58:08
I already got that much. That limit there is the problem...
- bobbym
- 2013-01-07 10:14:58
I am trying to put it into the required form but the algebra is hideous.
The above limit equals 1 / 2 . But the limit is very difficult to handle.
- anonimnystefy
- 2013-01-07 10:07:31
That is right.
- bobbym
- 2013-01-07 09:57:02
We are not allowed to split that limit?
Probably not, the two pieces are both equal to infinity.
- anonimnystefy
- 2013-01-07 09:54:32
Do you see the n/(p+1) part? It makes it not possible to use Stolz like that.
- bobbym
- 2013-01-07 09:51:59
We need to use the binomial theorem here now.
- anonimnystefy
- 2013-01-07 09:25:07
No. I already looked at that page. It just gets the limit to the indeterminate from 0*infinity...
- bobbym
- 2013-01-07 09:12:31
Hi;
Does this help?
http://topologicalmusings.wordpress.com … o-theorem/
- anonimnystefy
- 2013-01-07 08:45:52
Hi
Can anyone help me with the following limit:
I know that it should be equal to 1/2 and the the Stolz theorem is supposed to be used, but I cannot get the final result...