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I can't belive it's such a hard problem..IS there someone who can help??
This is just a thought, but in the second picture, could we move point C to the right a little bit and make it look like the first picture again? If that can happen without changing the ratio of AD:DC, then it could be done no matter where D is and so it would sort of be a proof, albeit a very sloppy one.
Still haven't solved it, but have some more ideas.
I have sat and looked at it for a while, but all I have come up with is what I mentioned.
Please If u could help me prove it I would be veary,veary happy it's veary important for me...
The diagram took a long time to load for me, so I have copied it here (click to enlarge)
Can someone help now please??
Yes this is exactlly the same diagram which they gave to me
A sketch would really help ... was there any diagram with it?
That problem statement is greek to me. Is that how they gave it to you? I'm sorry.
In triangle ABC which has acute angles Heights are cut across in point H.