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Topic review (newest first)

bobbym
2013-01-15 05:12:50

Hi Doubtful;

Looks like you do not need any help with that one you are correct! Very good.

Doubtful
2013-01-15 03:09:33

Thanks lot for your reply.

Can you pls help me with my other question:

What is the probability of choosing 2 malnutrition children out of all the children is it: (930/3000) * (929/2999)

bobbym
2013-01-10 03:55:09

Hi;

Since you said any two children,

(3000 / 3000 ) for the first child and (2999 / 2999) for the second child which equals 1. Not a very interesting pick.

A specific two kids,

(2 / 3000 ) ( 1 / 2999 )

Doubtful
2013-01-10 00:56:36

Any 2 different children

bobbym
2013-01-09 03:37:51

Hi;

Please, one question at a time.

2)

Any 2 different children? Or a specific 2 children?

Doubtful
2013-01-09 03:36:19

One more  doubt:

4. You mentioned the probability of choosing one child is 1/3000 and the probability of choosing one malnutrition child is 930/3000
How is it possible that the probability of choosing one child is less than the probability of choosing a malnutrition child?
should'nt the probability of choosing one child be more than choosing one malnutrition child?

Doubtful
2013-01-09 03:28:48

No problem at all... I appreciate your quick response.

About my other question:

2. Is the probability of choosing 2 children out of the total = 2 / 3000  or is it (1 * 2) / (3000 * 2999)

I have one more question:

3. What is the probability of choosing 2 malnutrition children out of all the children: (2 * 930) / 3000

bobbym
2013-01-09 03:05:39

Hi;

Yikes, of course you are right! A simple error on my part.

Doubtful
2013-01-09 01:52:58

Yes i understand any one child is 1/3000

But for malnutrition children it should be 930/3000, am i right here?

bobbym
2013-01-08 03:20:53

Hi Doubtful;

1. Is the probability of choosing one child out of the total = 1 / 3000

Child with malnutrition, 310 / 3000. Any particular child 1 / 3000.

Do you understand up to here?

Doubtful
2013-01-08 03:18:13

Hi,

Could you please help me with this question:

In your early post you mentioned one solution was:

1) By direct calculation
10 * (930*929*928*2070*2069) / (3000 * 2999 * 2998 * 2997 * 2996)

based on the above, would the below be right ?

1. Is the probability of choosing one child out of the total = 1 / 3000

2. Is the probability of choosing 2 children out of the total = 2 / 3000  or is it (1 * 2) / (3000 * 2999)

bobbym
2012-12-31 03:06:52

Me too! But I never had much luck wishing for things.

Roosh
2012-12-31 02:59:27

wish i was gifted =_=

Thanks A LOT for your time ! & I'll post my answers ASAP smile

bobbym
2012-12-31 02:48:43

It looks like a Poisson distribution problem.

We were just talking about a fellow who had an easy time with math. He was just about the smartest man that ever lived. The rest of us will have to struggle through it.

Roosh
2012-12-31 02:45:58

Moral of the story, never question what mothers think , because they just know! big_smile she definitely is right

*sigh* I'll give it another look then post whatever i come up with lol

It's a short Bio-statistics course , as a part of a postgraduate education , but math & statistics have always given me hard time hehe

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