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- anonimnystefy
- 2012-12-27 09:05:28
Yes, the answer is awesome.
See you later, then...
- bobbym
- 2012-12-27 07:21:09
Do you see how we could have gotten it from mine? The n^2/60 term is dominant for large n.
A really cool answer don't you think!
I will see you later, chores to do and thanks for working on the problem. You did great work with the formula.
- anonimnystefy
- 2012-12-27 07:20:06
Ah, I know what my mistake was! I calculated Gamma(3) to be 6!!!
Yes, it looks like it should be n^2/60.
- bobbym
- 2012-12-27 07:08:34
Check the post above you.
But now I am getting
That one works!!!!! Shortest one yet!
But if you use knowledge of landau notation you can see how we could derived it from my answer!
- anonimnystefy
- 2012-12-27 07:07:57
But, with α=0 that will just vanish...
- bobbym
- 2012-12-27 06:55:10
That problem is solved I had alpha as 1 instead of 0. Your form is right.
- anonimnystefy
- 2012-12-27 06:50:39
Hi bobbym
Where do you get the x from?
- bobbym
- 2012-12-27 06:39:57
Hi;
But something is wrong. If you are right you should have got a better answer than you did. I do not understand what is going wrong. I am rechecking everything please hold.
When I make your substitutions I get
- anonimnystefy
- 2012-12-27 06:34:37
Hi bobbym
You didn't substitute the rest of the parameters. α=0, β=3, A(x)=0, r=1.
- bobbym
- 2012-12-27 06:33:07
See what you put into B(x) it does not equal the original generating function. What is in the denominator of your B(x) does not get to the the denominator of the asymptotic form.
- anonimnystefy
- 2012-12-27 06:27:19
I do not understand you...
- bobbym
- 2012-12-27 06:26:05
When you put that into B(x) you will not get the original gf back.
- anonimnystefy
- 2012-12-27 06:24:50
Why not? It is analytic...
- bobbym
- 2012-12-27 06:22:02
Hi;
I do not think you can do that with B(x).
- anonimnystefy
- 2012-12-27 06:19:39
Hi bobbym
Now we have α=1, β=3, A(x)=0, r=1,