Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

## Post a reply

Write your message and submit
|
Options

## Topic review (newest first)

muxdemux
2012-12-24 15:13:01

That's a start! Once you've got that, you should divide both sides by

Notice that

and you should be able to use that second rule I gave you.

BarandaMan
2012-12-24 13:56:03

#### muxdemux wrote:

I just wrote

then did a bunch of algebra. Some things to remember while working it out:

and

Good luck!

Thank you! So based on the first rule you said, then (Pi/Pt)^(1-n) = (Pi^(1-n)(Pt)^(1-n)...which isn't the answer. Can you help??

muxdemux
2012-12-24 06:36:56

I just wrote

then did a bunch of algebra. Some things to remember while working it out:

and

Good luck!

BarandaMan
2012-12-24 01:05:31

Why does

((Pt)^(n-1))((Pi)^(1-n)) EQUAL the term ((Pi/Pt)^(1-n))? Apparantly these two are equivalent? I am not good at rearranging / how to change the signs on powers etc, can someone explain?

Thanks

## Board footer

Powered by FluxBB