Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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Not a problem, keep bugging us. Many brains make light work.
Thank you for the input. I have seen the R=bv equation but I have not seen the other. That one looks the most promising to date. The v portion will prove to be difficult as a secondary function will need to be performed that needs to factor in the increasing vertical and diminishing horizontal speeds (the bike is powerless in midair) and also to include gravity with all of that to be continually updated as the bike travels through it's arc. To add to the difficulty, the slope of the landing ramp needs to be factored in as well.
Air resistance is a tough nut to crack, because it can behave in complex ways. My physics textbook gives only two:
Coool ... I am glad I was able to help!
Outstanding. I put it together in an Excel spreadsheet with the ratio function you suggested and it works great. Thank you so much for your help. On to bigger and better things.
If you mean the horizontal distance is the only one that counts, then that can be calculated by ratio.
Thank you for the response, I'll be more patient this time. I was unable to figure out how to attach my drawing that I'm sure would help a great deal. Yes, I did get 127 for the adjacent of the large triangle. I lost you at the point you stated that a new smaller triangle has been created that measures "up the slope 52'". I came up with 54.6' up the slope as I calcualted 130' - 75'. Like I say, I'm lost.
Give a day or so for someone to respond ...
I guess I'm no fun. What am I missing here to make it fun enough to respond to??? Am I missing work performed to this point?
I can't quite figure out the formula required to determine the true adjacent side distance that corresponds to a measured distance down the slope of the hypotenuse when the overall opposite and hypotenuse sides lengths are known on a right triangle. The opposite side is 28 feet tall, the hypotenuse is 130 feet long and the measured distance down the slope of the hypotenuse is 75 feet. How do I derive the corresponding distance along the adjacent axis?