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Topic review (newest first)

jacks
2012-12-15 15:03:36

Thanks Bobbundy Got it.

bob bundy
2012-12-14 07:20:52

Ok.  Let's say P is (a,b) Q is (c,d) and R is (e,f)

a,b,c,d,e and f are all rational ie they are fractions

Midpoint PQ



and centroid is



the {rationals} are closed for +, - , x and 

ie. adding two fractions, or subtracting one fraction from another, or multiplying two fractions or dividing them will always give another fracftion.

Therefore both the midpoint and the centroid have rational coordinates.

Bob

jacks
2012-12-14 06:56:45

Thanks bob bundy

but I did not understand the meaning of the Given line

R is also rational so the point one third of the way up from PQ towards R will be rational

bob bundy
2012-12-14 03:11:27

hi jacks

Hhhmmm.  This is a new problem for me.  But I suppose you could tackle it like this:

centroid:  is at the intersection of the medians (which join the midpoint of a side to the opposite vertex, and is also one third of the way up any median.

So if P and Q have rational coordinates so will the midpoint of PQ.

R is also rational so the point one third of the way up from PQ towards R will be rational.

How does that sound to you?

Bob

jacks
2012-12-13 22:43:32

if the vertices P, Q, R of a triangle PQR are rational points

Then which of the following points is(are) always rational point(s)

options.

(a)centroid  (b)incentre (c)orthocentre (d)circumcentreplz explain answer

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