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bob bundy
2012-12-04 05:12:15

OK.  That'll do.

Bob

2012-12-04 05:05:17

Maybe if I re-write it.

3^(x+7)=6

bob bundy
2012-12-04 04:45:38

I'd do it like this:

Unfortunately, that's where this question unravels because you'd need to go into complex number theory to sort out log(-1).

This sort of thing happens if you make up a question at random.  (And you thought it was easy for a teacher to throw some questions together)

Bob

2012-12-04 04:12:01

That trick makes a lot of sense, but, what about when one number cannot be the same? Like the 6 below:

3^x+7=6

bobbym
2012-12-04 01:26:14

You now have

Here is a trick to these types whenever the bases are the same

you can ignore them and just solve the equation that you get from the exponents.

2012-12-04 01:23:03

I'm not sure. I think I don't understand.

bobbym
2012-12-04 01:18:34

Hi;

You can convert that expression on the right to be

2012-12-04 01:15:20

Sometimes I get x = -1/3 so Im not sure whats the right way to do it. :-(

bob bundy
2012-12-03 23:58:52

Welcome to the forum.

That answer looks good to me.

Bob