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  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

bob bundy
2012-12-03 19:42:06

hi shidubravin

Welcome to the forum.


(tan4A+tan2A)(1 - tan23A tan2A) = 2tan3A sec2A

Did you mean 23A here ?  substituting A = 10 gives a LHS ≠ RHS.

please check your identity.

Also, you have posted in the exercises section => you are challenging us to find the solution you already know.

Did you want it in the help section => you want someone to help you to do the problem ?

Bob

shidubravin
2012-12-03 14:24:37

(tan4A+tan2A)(1 - tan23A tan2A) = 2tan3A sec2A

2tan3Asec2A

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