Take the positive square root if h is increasing with respect to t, the negative square root if decreasing.

pokrate

2012-11-26 04:41:32

Thanks for the reply. Hopefully I will make some big leap forward with this thing.

scientia

2012-11-26 04:11:58

pokrate

2012-11-26 01:51:14

I always wondered about dx.dx ? How to handle that ? If I consider a small triangle with height = dy, and width dx, then hypotenuse dh = sqrt(dy^2 + dx^2). Now suppose I want to differentiate this equation wrt time t, what we will get ?