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n872yt3r
2013-01-26 22:26:12

I'm thinking you stole my idea because I did the same thing on a thread of 3 kissing circles with bobbym.
And the 4 circles etc. is for my upload on the GeoGebra Forum and on this site where you can upload GeoGebra programs.

Agnishom
2013-01-26 14:06:27

Hi n872yt3r.

n872yt3r
2013-01-23 03:49:24

Keep this comment up; I'm linking it to the GeoGebra Forum.
There are:
4 Circles
22 Squares
24 Triangles
66 Rectangles
72 Irregular

n872yt3r
2013-01-23 03:15:01

Did you steal my idea?

bob bundy
2012-11-23 00:38:45

Certainly.  Geometry and I have a long and happy relationship.

Bob

Agnishom
2012-11-23 00:36:46

I see
Thanks
However I will like to ask you again if I have any doubts

bob bundy
2012-11-23 00:28:51

OK.  Another diagram below.

This one shows a circle in the middle (B) and one on the left that crosses it (A) and one on the right that just touches it (C) .

The tangent to B where it crosses A cuts A again.

The tangent to B where it touches C is also a tangent for C.

General rule.  When two circles touch they share a common tangent.

A tangent is always at right angles to the radius at the point where the tangent touches.

So back to the previous diagram:

ABC = 90.  If you give a letter to a fourth point, you'll complete a square.  So BC = r

And AD is perpendicular to the common tangent at D (haven't drawn this line) and DC is too.

So ADC is a straight line.

Bob

Agnishom
2012-11-23 00:17:48

WOW! Thats a great proof

But what if the examiner asks me How do I know that BC = r (apart from intution)?

bob bundy
2012-11-22 20:03:24

hi Agnishom

See diagram.  Let the radius of the little circle be R

AB = BC = r

AC = R + r (why?)

So you should be able to use Pythagoras here.

Bob

Agnishom
2012-11-22 14:00:35

If the radii of each of the outer circles is r then show that radius of the inner circle is