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  Discussion about math, puzzles, games and fun.   Useful symbols: √ ∞ ≠ ≤ ≥ ≈ ⇒ ∈ Δ θ ∴ ∑ ∫ π -

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Topic review (newest first)

juukii
2005-11-07 06:55:47

Please help!!

juukii
2005-11-05 22:40:54

No one can't help me?? ;(

juukii
2005-11-05 01:48:09

Is there anybody who can solve it...please it's important

juukii
2005-11-03 08:38:51

I've tried to solve it in many ways but I still have nothing... sad

MathsIsFun
2005-11-03 07:40:51

I have an idea for a start.

Using: a + b + c - 1  is divisible by "p"
Perhaps only a + b can be divisible by p, so subtracting 1 requires adding 1, and that is the c term

Also:
a + b + c - 1 = p
( a + b + c - 1 )  /  ( a + b + c - 1 ) = whole number

That is as far as I have got, and I have to go do something else now.

juukii
2005-11-03 07:03:11

We have  p > 3  where "p" is number first and a,b,c which are all-out and positive and we know that    a + b + c = p + 1
and a + b + c - 1  is divisible by "p".
Prove that one of a,b or c     equal 1

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