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zetafunc. wrote:Then, I think f can take on any real value.

Then, I think f can take on any real value.

That is true. You can even plot it to see that the range is R (ie. the reals).

so I . the set should be infininte

yes for n=2, [n]=2 but when n=1.6, [n]=1

Is [x] the floor function, then? (e.g. [6] = 6?)

I think the set will be infinite. does anyone has anything else in mind?

f(x)= [x] + (x-[x])^2.where [x] means largest integer not exceeding x.then find set of all values taken by f