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## Topic review (newest first)

anonimnystefy
2012-11-21 05:21:57

#### zetafunc. wrote:

Then, I think f can take on any real value.

That is true. You can even plot it to see that the range is R (ie. the reals).

princess snowwhite
2012-11-21 04:12:54

so I . the set should be infininte

zetafunc.
2012-11-21 04:07:19

Then, I think f can take on any real value.

princess snowwhite
2012-11-21 04:01:03

yes for n=2, [n]=2 but when n=1.6, [n]=1

zetafunc.
2012-11-21 03:40:27

Is [x] the floor function, then? (e.g. [6] = 6?)

princess snowwhite
2012-11-21 03:35:57

I think the set will be infinite. does anyone has anything else in mind?

princess snowwhite
2012-11-20 20:02:23

f(x)= [x] + (x-[x])^2.
where [x] means largest integer not exceeding x.
then find set of all values taken by f

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