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- anonimnystefy
- 2012-11-21 05:21:57
zetafunc. wrote:
Then, I think f can take on any real value.
That is true. You can even plot it to see that the range is R (ie. the reals).
- princess snowwhite
- 2012-11-21 04:12:54
so I 
. the set should be infininte
- zetafunc.
- 2012-11-21 04:07:19
Then, I think f can take on any real value.
- princess snowwhite
- 2012-11-21 04:01:03
yes for n=2, [n]=2 but when n=1.6, [n]=1
- zetafunc.
- 2012-11-21 03:40:27
Is [x] the floor function, then? (e.g. [6] = 6?)
- princess snowwhite
- 2012-11-21 03:35:57
I think the set will be infinite. does anyone has anything else in mind?
- princess snowwhite
- 2012-11-20 20:02:23
f(x)= [x] + (x-[x])^2.
where [x] means largest integer not exceeding x.
then find set of all values taken by f