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Topic review (newest first)

math
2005-11-02 20:19:52

the teacher were given me ( can you post the solution )

MathsIsFun
2005-11-02 15:46:28



Code:

[math]1/[a\sqrt{a+b}] + 1/[b\sqrt{b+c}] + 1/[c\sqrt{c+a}]  \geq 3/[\sqrt{2abc}][/math]

Another tough one from "math" ... where do you get them?

Is the solution possibly geometric?

math
2005-11-02 15:22:55

a,b,c>0 . Prove the inequality :
1/[a.\sqrt{a+b}] + 1/[b.\sqrt{b+c}]+1/[c.\sqrt{c+a}]    >=  3/(\sqrt{2abc}

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