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the teacher were given me ( can you post the solution )
[math]1/[a\sqrt{a+b}] + 1/[b\sqrt{b+c}] + 1/[c\sqrt{c+a}] \geq 3/[\sqrt{2abc}][/math]
Another tough one from "math" ... where do you get them?Is the solution possibly geometric?
a,b,c>0 . Prove the inequality :1/[a.\sqrt{a+b}] + 1/[b.\sqrt{b+c}]+1/[c.\sqrt{c+a}] >= 3/(\sqrt{2abc}