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Topic review (newest first)
- bobbym
- 2012-11-12 04:39:48
I would think it is a typo.
- BarandaMan
- 2012-11-12 04:20:14
I did the question from a book, and in the back ith as the answers. The first line of my original post shows what the answer is in the textbook. It must be wrong, I will write a letter. It is simple inequality I thought... must be printing error.
- bobbym
- 2012-11-12 04:14:04
Hi;
The answer book? What is that?
- BarandaMan
- 2012-11-12 04:09:09
Hey!
That is exactly what I got! Thank you. That is why I am confused, because the 3pq I posted it in the ANSWER BOOK. Which is why I am confused by this!
It cannot be the answer from the inequality!
- bobbym
- 2012-11-12 03:36:11
Hi;
Subtract 6pq from both sides.
Divide both sides by 3.
Divide both sides by (1-p)(1-q) provided that p,q are both less than 1.
I do not know where the 3 comes from in your question.
- BarandaMan
- 2012-11-12 03:21:40
Yes I do! That is what the answer says but i do not understand how it gets past the 'implies' after rearranging
- bobbym
- 2012-11-12 03:17:08
Hi BarandaMan;
Do you mean
- BarandaMan
- 2012-11-12 03:00:47
9pq < 6pq +6(1-p)(1-q). Implying that 3pq/(1-p)(1-q) < (less than or equal to) 2
PLEASE explain this somebody! I don't understand how this works? Does it not equal 3<6(1-p)(1-q)?
Please walk me through this. Thanks.