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hi mathteacher005 numberempire.com/limitcalculator.php?fu … =twosided Bob
Hello! The answer is \lim_{x\to\infty }\left({{2\,{\it cx}+1}\over{12\,{\it cx}}}\right)^{{{1}\over{x}}} = 1.
I use Schick's or Gillette's razor for a better shave.
Being simplest doesn't makng true. And, yes, I am familiar with the Occam's razor.
Isn't the simplest typo that she wrote 4 when she meant 1?
This looks too much like a book problem. I do not think that is what it wants.
Maybe the questioner just wants the OP to see that the answer is 1. To spot the inconsistency.
Yes. So I am thinking that it might be a typo of the function whose limit is being taken.
There is no c that will give a limit of 4. You said so yourself. The limit is independent of c. That is why it is trivial.
Not really. The question would be close to trivial. I think the question is more likely to be asking for the constant c for which a limit has the value 4 and then finding the same limit but with 2c instead of the c, whose value we now know.
But doesn't it follow?
I don't think that is the misprint.
Yes, it should read 1 instead of 4.
So the answer should be 1 because 2c=c.
Maybe it is a misprint or a typo.
Hi; 