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- zetafunc.
- 2012-10-26 03:25:29
Also, for (1+i)!, you can find that using bobbym's answer, since
- bobbym
- 2012-10-25 22:41:49
For i! use this truncated series:
Substituting z = i you get
- Kenjiska
- 2012-10-25 21:45:46
What about the others
(1+i)!
i !
- bobbym
- 2012-10-25 20:43:25
Hi;
Those are all difficult but here goes nothing!
Let's try (.1)! first. For that we use a series and a trick.
It is in nested or Horner form for fast computation. The series is best for values >=5 so we put in z = 5.1
We take the exponential of both sides and get.
Now to get .1! we use a simple relation:
So
- Kenjiska
- 2012-10-25 19:19:34
Show me using the taylor series
- bobbym
- 2012-10-25 15:45:29
Hi;
(-1) ! does not exist. All the negative integers of the factorial function are equal to infinity.
I would use a Taylor series for some of them. How much accuracy do you need.
Basically though you would use a computer or Wolfram Alpha to look those up. If your teacher wants to see some method then how is it you do not know that method? If I use series expansion he/she may not want that method used. So provide me with what method is to be used.
- Kenjiska
- 2012-10-25 13:46:44
Please,tell me the value of these-
i !
(-1) !
(1+i) !
(.1) !