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Topic review (newest first)
- anonimnystefy
- 2012-10-08 11:02:37
Where can you get with the substitution x=(b-a)-a*cos(theta)?
- bobbym
- 2012-10-08 08:06:24
Checking them now.
Yes, they are the same.
- zetafunc.
- 2012-10-08 07:50:36
These two integrals are identical...
- bobbym
- 2012-10-08 07:41:24
Hi;
Alpha has a time limit. I do not think those two integrals are the same so something is wrong somewhere.
- zetafunc.
- 2012-10-08 07:29:30
Never mind, forget W|A, it is unable to solve the problem so I do not trust its solution.
- zetafunc.
- 2012-10-08 07:26:16
Hmm, I am skeptical about that last line. According to W|A it is giving me a horrendous-looking solution.
- zetafunc.
- 2012-10-08 07:16:10
"(i) Use the substitution x = 2 - cosθ to evaluate the integral
(ii) Show that, for a < b,
where
and ."
I have done the first part and got
which is correct (according to WolframAlpha). But the second part of the question confuses me. I have done this:
Let x = (b - a) - cosθ, then dx = sinθdθ
and I have ended up with this:
but I do not know where to go from here. Help would be appreciated.