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- bobbym
- 2012-10-12 04:27:07
Hi;
Looks like a typo.
- Shivamcoder3013
- 2012-10-12 01:16:28
The solution provided by my professor is 1/131, with no direct clarification of the answer.
- Shivamcoder3013
- 2012-10-11 23:58:30
I submitted my results today at Yale and recieved an almost-perfect mark. Apparently, my answer to the particle question, despite the fact that Bobbym agreed with me, is incorrect.
- bobbym
- 2012-10-10 08:58:06
Yes, I always try to use the username. It is the name the person chose to sign in here so it is obviously there preferred moniker.
- anonimnystefy
- 2012-10-10 08:55:39
Yes. You said so yourself.
- bobbym
- 2012-10-09 21:23:31
Are you sure about that?
- anonimnystefy
- 2012-10-09 18:50:50
bobbym calls everybody by their forum username.
- Shivamcoder3013
- 2012-10-09 10:16:43
Oh, okay. By the way, you can call me Shivam or Cless. Anyways, I didn't go to Yale today so I will submit my results later.
- bobbym
- 2012-10-08 14:18:18
Hi Shivamcoder3013;
What anonimnystefy is saying is just because you go to infinity that does not mean you have found a maximum. There is a way to prove have the largest value at 75.
- Shivamcoder3013
- 2012-10-08 12:36:40
By the way, I apologize for my improper LaTeX syntax.
- Shivamcoder3013
- 2012-10-08 12:34:58
Well... Using L'Hopitals Rule, we simply take the derivative of the numerator and the denominator separately to get
. Then simply calculate the limit by cancelling the terms to receive the final answer 75.- anonimnystefy
- 2012-10-08 11:04:04
Yes, and that is what is needed to be done in order for the proof to be complete.
- bobbym
- 2012-10-08 06:16:19
That is very good and true. There is a way to determine where the maximum value is and prove that it occurs at infinity.
- anonimnystefy
- 2012-10-08 04:42:02
Not true. That just gets you the limit, but doesn't guarantee that that value is the maximum of the function.
- bobbym
- 2012-10-07 23:19:17
You prove it by taking the limit of that function.