Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
| |
|
|
You are not logged in. Post a replyTopic review (newest first)
Hi Anakin;
Alright then, I'll go with that as well. Plus it fits the formula from the page you linked. 5 hours until class, I'm gonna catch some sleep.
Whenever I have seen the derivative operator in front of an integral like that they have always meant
That's exactly what I've got above as well. I'm not sure whether you're simply checking if my work was free of errors or whether that is the solution to the question. Could you clarify?
Hi;
Hi Bobbym,
Hi Anakin;
Hi,
Hi Anakin;
Bob: If one was to change the variable in the function, wouldn't the intervals on the integral also change?
Hi;
hi Anakin, In other words you can substitute into the integral process any alternative variable. So I cannot see why you should just 'cancel out' the integration with the differentiation and just sub in the limits. This worked OK with a simple function, but, I confess, I'm not 100% sure on this. As the day moves ahead, hopefully we'll get a second opinion on this. Bob
Hello! I was just working on a review assignment and in the 10% or so left, I've come across a question for which I have no idea on how to begin. |