You are not logged in.
Post a reply
Topic review (newest first)
- anonimnystefy
- 2012-07-30 20:35:23
You're welcome. But I am sure you are not crazy.
- debjit625
- 2012-07-30 19:58:37
Ok ,I was going to ask to you to show the steps but suddenly I realized that I have got it...
Actually I answered my question in post #9
Thanks for your time bro, "talking to you made my crazy mind to work"
- anonimnystefy
- 2012-07-30 19:46:59
Moving everything shouldn't change anything.
- debjit625
- 2012-07-30 19:24:15
anonimnystefy wrote:
That is my solution with the plus/minus sign inside the root taken as +. I am sure taking the minus sign would work as well.
No the minus will not work in this case , as we are finding y^2 and y^2 cant be negative.
But thats not the big problem of mine...my problem is that I can't get to the answer using this equation
And the correct answer for x and y in my book and every where else is
Another thing I want to say,when I write the equation
to this,i.e.. moving the equation from one side to another
I get correct answer.Is here I am doing something wrong?
- anonimnystefy
- 2012-07-30 19:00:13
Hi debjit625
That is my solution with the plus/minus sign inside the root taken as +. I am sure taking the minus sign would work as well.
What did you say the correct solution should be?
- debjit625
- 2012-07-30 18:56:29
anonimnystefy yes what you got I also got that using that equation,but things changes when I use
The correct answer will be
And thanks for reply
- anonimnystefy
- 2012-07-30 18:55:44
Hi debjit625
What do you get as the answer and what does the book get as the answer?
- debjit625
- 2012-07-30 18:49:29
Ok before you guys think too much let me tell you where I got this from...as I said its about square root fo a complex number
Let z be a complex number
and its square root be c
Then
So
--- Eq1
--- Eq 2
Now every where they (in books,resource,etc) find x using quadratic formula, and after that they substitute x in Eq2 to find y.But what I am doing is I am trying to find y using quadratic formula ,but my signs(+/-) doesn’t matches. I think its math and what process we take it doesn’t matters ,the answer will be always same. I must be doing something very very silly...which is not coming into my mind right now but it will come later it always happens with me.
- anonimnystefy
- 2012-07-30 18:34:44
Hi debjit625
Is this what you get?
- debjit625
- 2012-07-30 18:26:24
No you didnt got my problem ,I know that I am solving for y^2,and after solving for y^2 I have to remove the square,The problem is different just solve it and I will tell it about...
Actually I am solving for this
- anonimnystefy
- 2012-07-30 18:20:21
Hi debjit625
Try to substitute y^2=t when you get the quadratic. The solve for t and y will be just the plus/minus square root of it.
- debjit625
- 2012-07-30 18:12:59
Hi all I am having problem with this qudratic equation with signs ,or I am doing something silly ,its all about square root of complex number.
------Eq 2
We can write Eq 2 as
Now we can write Eq 1 as
Is my last equation correct? (I hope so),if yes please solve it using qudratic formula ,as far you can
I have did it but my answer is not matching with correct answer got from other process.The sign is not matching but yes if I write the last equation like this
,my answer matches.
Thanks