Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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bobbym
2012-07-30 00:21:01

Hi;

On the other hand, perhaps you were hoping for female admiration

A person like that could be described as a wolf or maybe just a darn fool.

What I mean is:  " I know you and I admire you more every day."

That was my feeling about you so you can not borrow it.

bob bundy
2012-07-29 23:36:39

hi bobbym,

Who do you count as " someone I knew" ?

Does it have to be past tense?

What I mean is:  " I know you and I admire you more every day."

On the other hand, perhaps you were hoping for female admiration, in which case, I cannot help you there.

hi 295Ja

You are welcome.

Bob

bobbym
2012-07-29 23:25:25

Hi;

bobbym I can't help it but to admire you more.

If only someone I knew felt that way.

295Ja
2012-07-29 22:34:03

bob bundy thank you very much for being kind enough to explain further. I really appreciate it and I could say that I now understand it better.

295Ja
2012-07-29 22:30:19

bobbym I can't help it but to admire you more.

bob bundy
2012-07-29 20:14:38

hi 295Ja

Here is an example where 'cross-multiplying' has been done incorrectly.

Student remembers about cross multiplying, but does it incorrectly:

It is because of this sort of mistake that teachers advise against using cross multiplication.

I prefer to teach 'multiply every term by the same amount', so in the above example:

Another thing you may find helpful is to convert the algebra to numbers.

In my example, suppose u = 3, v = 6 and f = 2

In the original:

This is correct.

In the error version:

This is NOT CORRECT so the error is revealed.

In my correct version:

This has come out correctly.

This is not a guarantee that no mistake has been made as I might just have been lucky to get the 'right answer', but it will help to confirm that what you have done is right.

It is 11.14 am in the UK.

Bob

bobbym
2012-07-29 20:12:13

Do not admire me. I do not require much sleep and am capable of going without any for 36 hours or so.

295Ja
2012-07-29 20:07:52

Whooh! I admire you for being awake this time around knowing that it's an early morning there.

bobbym
2012-07-29 19:54:22

Hi;

It is 2:55 AM here.

295Ja
2012-07-29 19:52:50

Thank you for clarifying that to me!

I'm just curious, what is now the time at your place? By the way, I'm from the Philippines and its now 5:55 pm here.

bobbym
2012-07-29 19:32:08

Hi 295Ja;

Welcome to the forum.

I think you are mistaking the term cross multiplying for division. You may never divide by 0 unless it is stated in the problem that x ≠ 0.

So if a variable might be 0 you should not divide by it. In this case from the formulation of the problem you can see that they are saying x ≠ 0.

I hope you won't mind if I'll visit this forum more often and post problems I'll find confusing in the future.

That is the purpose of the forum. It is a place where like minds can freely share information.

295Ja
2012-07-29 19:15:28

Bob thank you for helping! I hope you won't mind if I'll visit this forum more often and post problems I'll find confusing in the future.

May I just ask for one clarification? I remember my teacher told us that we must avoid doing cross multiplication
when there is a variable involve. But I just noticed that  to arrive on the answer to my question, x must be cross multiply to -3±√ 17.  If I'll just state on my solution that x≠0, will it be allright to do a cross-multiplication?

bob bundy
2012-07-29 18:16:59

hi 295Ja

Welcome to the forum!

That method is the one I would have chosen and you have done it correctly.

Alternatively you could substitute y = 1/x and make a quadratic in y.  It would be more complicated because you'd have to expand the bracket squared.

Or you could clear the brackets from the original, (more complicated) then times by x^2 to clear the fractions.  Again, more steps.

so

I've checked these in the original and both work ok.

Hope that helps!

Bob

295Ja
2012-07-29 16:25:45

-7((1/x)-1)=4+2((1/x)-1)^2

Here's what I did:

I let w= (1/x)-1

So I have:

-7w=4+2w^2
2w^2+7w+4=0

Then I  factored it using quadratic equation so I've got:

w= (-7±√17)/4   *Note: √17 is square root of 17.

Since w= (1/x)-1

(1/x)-1= (-7+√17)/4  and (1/x)-1= (-7-√17)/4

I find it hard  to evaluate the value of x from the 2 equations I've got. Maybe I've done something wrong in simplifying these 2 or much worse,my entire solution is wrong.So please help me find the way out. I'm also looking for other way to solve it. If someone out there know it, kindly  share it to me. I would be very grateful for someone who'd help. I'd be waiting for replies then! Have a nice day!