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- M_TREY
- 2005-10-14 10:16:28
I got that answer right before i checked the posts. haha
- ganesh
- 2005-10-13 19:57:39
Let the pentagon be ABCDE
AB is 7,2,10
BC is 10,1,8
CD is 8,5,6
DE is 6,4,9 and
EA is 9,3,7
The total is 19 on all sides!
- MathsIsFun
- 2005-10-13 17:34:57
Would you have an illustration of this?
You can either link to one, or upload one (via "Post Reply")
- M_TREY
- 2005-10-13 10:22:45
You have a pentagon with three circles on each side. One on each corner and one in the middle. With a total of 10 circles. You need to put in a number 1-10 into each circle and you cant reuse any numbers. Each side needs to add up to the same sum. I read somewhere that the 4 possibilites make the sums of 14, 16, 17, 19. I solved the one for 14 but cant do the others. Any answers would be appreciated.