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So the angle netween a sloping side and the base is
I was trying to calculate the angle between two sloping sides.
My formula is
It took a page of algebra to get to this.
I'll post it if you ask nicely.
My expression is much more complicated.
Using your formula and with a = 4 and h = 3.265986 (which will make a regular pyramid = tetrahedron ) I got cos AGC = -5.9375 which is not possible!
I used my formulas and got angle = 70.528779 which is the Wiki value.
How did you get your expression?
I'll check your working.
Can you prove me right or wrong when i say: cosAGC 1-6h^2-2a^2)dvide by (a^2)
Hi bob? I did follow your work. The last part is like ok, but how u came to get GC, i didn't get it.
(iii) Find point G on VB so that CGV = 90
Second diagram shows true shape of VBC
(iv) The required angle is AGC
AG = GC
AC = a
I need a simplified formular for this. If not so explain how i can do it.
What is the angle between two adjacent plans of a equilateral triangular pyramid of length 'a' and the perpendicular height of the pyramid is 'h'?