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## Topic review (newest first)

bobbym
2011-09-30 02:16:23

Hi Deon588;

Your welcome. What year are you in?

Deon588
2011-09-30 02:13:34

Thanks a lot Bob and Bobbym.  I have done this many times before but the way the question was written confused me a bit

bob bundy
2011-09-30 01:59:46

hi Deon588

will do nicely.

(But using the 'a' and 'b' from the new quadratic, of course.)

Bob

bobbym
2011-09-30 01:14:31

Hi Deon588;

Yes, there is a way using just algebra.

Deon588
2011-09-29 20:02:29

Hi Bob.  Differential calculus is not part of my course this year at all.  So I can find x either by completing the square or

?
If i'm asking for help too much lately please let me know.  I have exams in 3 weeks so trying to get everything cleared up before the exam.
Thanks

bob bundy
2011-09-29 17:51:32

hi Deon588

d(BA)/dx is a special notation used in the differential calculus.

It gives you a way of finding the maximum value of an expression (amongst many, many uses!).

It's too big a topic to start in answer to the question, if you haven't met it before.

But don't worry.  As the expression

is a quadratic there's another way to get the maximum value.

I've put the graph below.  As you can see it does have a maximum value.  Would you be able to work out the x, at this point?

Bob

Deon588
2011-09-29 17:33:41

Hi Bob.  I did exactly that up to the point

Thanks

bob bundy
2011-09-29 11:03:09

hi Deon588

I got a = -2    b = -4    and c = 0

Then for the points:

So

So you need

Can you take over from here?

Bob

Deon588
2011-09-29 09:00:09

Hi Bob I have the parabola and lines equations.  So to find the maximum I subtracted the line's equation from the parabola's equation but from here i'm not sure.

bob bundy
2011-09-29 07:56:48

hi Deon588,

Have you got a, b and c yet?

I'll assume yes.

That fixes the parabola (ie. there's only one answer) and the line is obviously unique.
But B can move about on the parabola and so that means M moves too.

I'd call M (x,0) and write the coordinates of B and A in terms of this.

Then you write an expression for BA in terms of x, differentiate, and hence get the maximum.

I'd better go and get a piece of paper and try it out.

Bob

Deon588
2011-09-29 07:31:35

Hi.  I am a bit confused with this question the question is "Find the coordinates of M when BA is a maximum"  Should I subtract the straight line from the parabola and then

I don't understand how BA has any effect on M?  Doesn't M just stay where it is on the x-axis?
Thanks a lot in advance