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Well, here is the complete, static, problem:
Wow, that is alot more complex than I thought. Tanks!
Anyone want to take this further?
Thanks, I'm looking forward to the continuation. I tried to do some moves but it got messy!
I have a few minutes ...
Cheers for ur time guys. MD/H and MR/H are not the same, and I guess Im still stuck trying to solve for C1. It has been a while since I used the taylor expression, so I can't see how it would simplify in providing an expression for C1...
cosh(x) can be approximated with a taylor expansion.
I will trust you on the formula, seems reasonable anyway as a simple catenary has the formula y = a cosh(x/a)
And the inverse:
If I had a bit more time I would try brute algebra on it, to see where we get to.