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That is not correct.
Shouldn't this be
to be clear I am talking about (sin(t))^2
Wolfram is going to put it in terms of the Dirac delta function, which I think is a step function.
Also what is the notation for a Fourier transform? For Laplace it's a fancy L, is it a fancy F for Fourier transforms?
Sorry if it's a bother but do you know how to compute Fourier transforms? I'm trying to learn how, I've seen the Wikipedia article and saw this:
Does this mean that if I put in some function of x, such as sin(x), I'll get f(ξ) where ξ is a real number? Not sure, I'll post my working in a second. Sorry if I sound stupid...
I wasn't given an interval for s, sorry. I am just waiting for my GCSE results (I turn 16 in August) and I'm just trying to extend my knowledge of calculus. I want to learn about Fourier transforms too hopefully but I need some practice with that.
Then evaluate RHS at 0 and subtract that from the evaluation at infinity. I got 0... so then we have
Therefore assuming s > 0.
I also tried the Laplace transformation for sina(t) and got .
The LHS has to be evaluated at infinity and then you subtract the evaluation of it at 0. The RHS is untouched.
How are you getting 0 for the LHS?
If s is very small then the LHS is not zero. Were you given some interval for s?