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Topic review (newest first)
- Flowers4Carlos
- 2005-09-14 05:54:05
hi yaz josh!!!
i'm going to take a wild guess and say this is problem #32... am i right??? 
f + g = (1+x)^(1/2) + (1-x)^(1/2)
that's it!!!! why?? we cannot add radicals.
f - g = (1+x)^(1/2) - (1-x)^(1/2)
that's it!!! why?? we cannot subtract radicals.
fg = (1+x)^(1/2) * (1-x)^(1/2)
use the property (ab)^(1/2) = (a)^(1/2) * (b)^(1/2)
[(1+x)(1-x)]^(1/2)
(1-x^2)^(1/2)
f/g = (1+x)^(1/2) / (1-x)^(1/2)
use the property: (a/b)^(1/2) = (a)^(1/2) / (b)^(1/2)
[(1+x) / (1-x)]^(1/2)
that's it buddy!!
- Josh
- 2005-09-13 08:16:17
Well, it's the beginning of the year and I'm already stumped :-X.
The problem tells me to add, subtract, multiply and divide two given functions, but I am not sure how to continue since they are square roots.
Here are the functions:
f(x) = sq.root(1+x) and g(x) = sq.root(1-x)
Find: f+g, f-g, fg, and f/g
Any help is much appreciated. 