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Topic review (newest first)

kylekatarn
2005-09-15 01:50:39

Code:

    √2arctan(x√2) 
x - -------------- +C
             2
seiya_001
2005-09-14 16:31:22

I hope this helps...
your problem is:
∫2x^2/(2x^2+1) dx

divide 2x^2/(2x^2+1) to acquire 1-(1/2x^2+1)

then: ∫ 1-(1/2x^2+1) dx = ∫dx - ∫(1/2x^2+1) dx, yay..an easier integration...!!
                                    = x-∫(1/2x^2+1) dx, and we know that ∫1/(u^2+a^2) dx = 1/a arc tg u/a
thus: x- (arc tg x√2) or x(1-arc tg √2) + C

guys please CMIIW...

kylekatarn
2005-09-13 10:42:54

try the substitution
z=2x
and then integrate by parts.
I haven't solved it, but at a first glance seems a good approach.

Archon
2005-09-13 00:33:51

hey im in college level calc and i am wondering if you could help me with this problem

∫2x^2/(2x^2+1) dx

thx for all your help

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