If a = b then it will execute 1 time.

Use the formula, if a = b and c =d then the body will be executed:

( b - a + 1 ) ( d - c + 1 ) = ( 0 + 1) ( 0 + 1 ) = 1 time

And wait, I forgot to mention this. Why are you asking this question? All you have to do to answer this for yourself is program two loops and put a print statement between them. You are both missing the whole point of programming. It is to answer experimentally, questions like this.

Hi umasou;

Welcome to the forum! There is still a unique answer. The body of the loops will executed ( b - a + 1 ) ( d - c + 1 ) times.

This is assuming an increment of 1.

Hi mantastrike;

The innermost k loop goes from 1 to m. If a loop goes from 1 to 5, that is 5 times. If it goes from 1 to 100, that is 100 times. If it goes from 1 to m that is m times.

Now the j loop goes from 1 to n. That is n times. Each time the j loop counts once the k loop goes m times.

So the two inner loops are n*m

The i loop goes from 1 to 17. Each time the i loop executes the j and  k loop execute n*m

So all three loop s are 17 * n * m