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Topic review (newest first)
- bobbym
- 2010-06-20 03:22:19
Hi lakeheadca;
We have the 2 equations:
P = 100 = 2L + 2W
A = 25 = L * W These are easy. But not easy to solve for all those variables. So we try to eliminate one. We solve for the L from the first equation.
L = 100 - 2W = 50 - W
25 = L * W Substitute 50 - W for L
25 = ( 50 - W ) W This is a quadratic, so expand it.
25 = 50W - W^2
W^2 - 50 W + 25 = 0
Now solve by the quadratic formula. Are you Okay with this? Or do you need more help? After you get the answer I will go over the equations with you.
- lakeheadca
- 2010-06-20 01:58:52
Please can you explain that actually what this question is asking. What this equation will do. I still don't know how to come up the equation. Am I finding length which is equal to this function. It is quadratic equation, so there are two W??
I am not good in math. Sorry.
- bobbym
- 2010-06-19 09:20:05
Hi;
Start by using the equations for A and P.
P = 100 = 2L + 2W
A = 25 = L * W
Solving from the first equation:
L = 100 - 2W = 50 - W
Can you finish from here?
- lakeheadca
- 2010-06-19 09:02:05
A rectangle or square with perimeter 100cm, area 25 cm² what will be the equation.
is it
w²+25w+100
w²+50w+25
w²+25w-100
the third option i dont remember.
Please explaine
thank you.