Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
You are not logged in.
Post a reply
Topic review (newest first)
Where c is the ratio of B to A in this case 1:2, So c = 1 / 2, c is always less than 1.
I am having trouble with setting the initial conditions. Okay , got it. If A starts at y=5 and B starts at ( 0 , 0 ) we set the initial conditions as y ' (5) = 0 and y(5) = 0
Solving the DE we get:
Plugging in x = 0 we get y = 10 / 3. So A will catch B at ( 0 , 10 / 3 ). This can be easily checked as being correct.
http://www.mathsisfun.com/graph/functio … 3333333333
Notice that A comes from the right and doesn't start at the origin, but to make it do so should be a simple translation.
Perfect, I'm also working on it right now actually. I'll update you if I manage to solve it!
Thanks bobbym!! That does help a lot!
Sorry, maybe I did not explain the problem well enough. "A's direction of movement is always in the nearest-distance-direction". So, A's direction will change according to B's movement. This will result in some sort of parable for A's path. NOT just pythagoras
Let the point A be (0, 0), i.e. origin, and lets say that they meet at a point C (b, k)